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Question

The sum of a two digit number and the number obtained by reversing its digits is always divisible by 


A
3
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B
9
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C
11
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Solution

The correct option is C 11

Consider the number ab
ab = 10×a + b
Reverse of ab is ba.
ba = 10×b + a
Sum of the number and its reverse is,
ab + ba = 10×a + b + 10×b + a
10×(a + b) + (a + b) =  11× (a + b)
It is always divisible by 11.


Mathematics

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