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Question

The sum of a two-digit number and the number obtained by reversing the digits is always divisible by


A

3

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B

4

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C

9

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D

11

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Solution

The correct option is D

11


Consider the number ab

ab = 10×a + b

Reverse of ab is ba.

ba = 10×b + a

Sum of the number and its reverse is,

ab + ba = 10×a + b + 10×b + a

10×(a + b) + (a + b) = 11× (a + b)

It is always divisible by 11.


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