Question

The sum of a two digit number obtained by reversing the order of its digit is 110. If the difference between the digit is 6. Find the numbers.

Answer 1

$$\begin{gathered} \mathrm{Dear}\mathrm{Student}, \\ \mathrm{Let}\mathrm{the}\mathrm{digit}\mathrm{is}\mathrm{xy}\mathrm{or}10\mathrm{x}+\mathrm{y}. \\ \mathrm{So}\mathrm{according}\mathrm{to}\mathrm{the}\mathrm{question} \\ 10\mathrm{x}+\mathrm{y}+10\mathrm{y}+\mathrm{x}=110 \\ 11\left(\mathrm{x}+\mathrm{y}\right)=110 \\ \mathrm{x}+\mathrm{y}=10......\left(1\right) \\ \mathrm{Also}\mathrm{x}-\mathrm{y}=6...\left(2\right) \\ \mathrm{Adding}\mathrm{both}\mathrm{the}\mathrm{equation},\mathrm{we}\mathrm{get} \\ 2\mathrm{x}=16\mathrm{or}\mathrm{x}=8\mathrm{and} \\ \mathrm{subtracting},\mathrm{we}\mathrm{get} \\ 2\mathrm{y}=4\mathrm{or}\mathrm{y}=2 \\ \mathrm{So}\mathrm{the}\mathrm{number}\mathrm{is}82 \\ \mathrm{Regards} \end{gathered}$$