The sum of ages of A, B and C together is 93 years. C is thrice as old as A and B is 18 years older than A. Then, the difference between ages B and C is?

30 years

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18 years

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12 years

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11 years

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None of the above

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Solution

The correct option is C 12 years
Let the age of A be = x
Then ages of B and C will be = x + 18 and 3x
Sum of their ages = x + 3x + x +18 = 5x + 18
$\Rightarrow$ x = 15
Difference between ages of B and C = 3x - (x + 18) = 45 -33 = 12

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The sum of ages of A, B and C together is 93 years. C is thrice as old as A and B is 18 years older than A. Then, the difference between ages B and C is?

The correct option is C 12 yearsLet the age of A be = x Then ages of B and C will be = x + 18 and 3x Sum of their ages = x + 3x + x +18 = 5x + 18 ⇒ x = 15 Difference between ages of B and C = 3x - (x + 18) = 45 -33 = 12

The correct option is C 12 years
Let the age of A be = x
Then ages of B and C will be = x + 18 and 3x
Sum of their ages = x + 3x + x +18 = 5x + 18
$\Rightarrow$ x = 15
Difference between ages of B and C = 3x - (x + 18) = 45 -33 = 12