wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The sum of all 2-digit numbers divisible by 5 is _________?

A
1035
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1245
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1230
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
945
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 945
The series will be : 10, 15, 20,.....,90,95
Sn=10+15+20+......+90+95
here a will be first term
a = 10
& d = difference b/w any
two terms
d = 5
series containing n terms
& n = 1+(Lasttermfirstterm)d
=1+(9510)5
n = 1 + 17 = 18
now, Sn=n2[2a+(n1)d]
=182[2(10)+(181)(5)]

=9(20+85)
Sn=9(105)
Sn=945


1180629_1068790_ans_e6604095d8df4495a42b2eb38eba4e1b.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometric Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon