The sum of all 3−digit numbers less than or equal to 500, that are formed without using the digit ′′1′′ and they all are multiple of 11, is
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Solution
The required numbers are 209,220,231,...,495
This A.P. contains 27 terms
Sum of this A.P. =272[209+495]=9504
Only 231,319,341,418 and 451 are not allowed in this sum.
So, required sum =9504−1760=7744