The correct option is B 1485
LCM(5, 3) = 15
Between 200 and 300, there are six numbers (210, 225, 240, 255, 270, 285) that are completely divisible by 15 and, hence are divisible by 5 and 3.
Thus, the progression is 210, 225, 240, 255, 270, 285.
Clearly, these numbers form an AP with a = 210, d = 225 – 210 = 15, n = 6.
Sn=n2[2a+(n−1)d]
⇒S6=62[2×210+(6−1)×15]
⇒S6=3[420+5×15]
⇒S6=3(420+75)
⇒S6=3×495
⇒S6=1485
Hence the correct answer option is (2)