The sum of all interior angles of a hexagon is
(a) $6$ right angles.
(b) $8$ right angles.
(c) $9$ right angles.
(d) $12$ right angles.

Open in App

Solution

Since, Sum of all interior angles of a polygon with $n$ -sides
$= (2 n - 4) \times 90^{\circ}$
i.e., $(2 n - 4)$ right angles
Now, Hexagon has $6$ number of sides.
$\Rightarrow n = 6$
Sum of all interior angles of a hexagon
$= (2 n - 4)$ right angles
$= (2 (6) - 4)$ right angles
$= (12 - 4)$ right angles
$= 8$ right angles
Hence, Option (b) is correct.

Suggest Corrections

Similar questions

S

n

S

2 \times 10^{8} m / s

2.4 \times 10^{8} m / s

△ A B C, (s - a) (s - b) = s (s - c),

C

2 s = a + b + c,

∣ ∣ ∣ ∣ ∣ \begin{matrix} a^{2} & {(s - a)}^{2} & {(s - a)}^{2} {(s - b)}^{2} & b^{2} & {(s - b)}^{2} {(s - c)}^{2} & {(s - c)}^{2} & c^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣

= 2 s^{3} (s - a) (s - b) (s - c) .

Join BYJU'S Learning Program