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Question

The sum of all roots of the equation

sin(πlog3(1x))=0
in the interval (0,2π) is

A
3/2
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B
4
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C
9/2
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D
13/3
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Solution

The correct option is B 9/2
General solution of this equation is,
πlog3(1x)=nπ, where n is any integer
x=3n
In (0,2π) n can take values,1,0,1,2,3,.........
So sum of all roots is,
=3+1+1/3+1/32+1/33+...................
=4+1/311/3 =4+12 =92
Hence, option 'C' is correct.

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