Question

The sum of all $s{p}^3,s{p}^2$ and $sp$ units present in solid $PC{l}_5$ , solid $PB{r}_5$ and solid $N_2{O}_5$ are:

• A. 4
• B. 3
• C. 2
• D. 5

Answer 1

The correct option is A 4

Solid $PC{l}_5\to \underset{\underset{s{p}^3}{\downarrow }}{[PC{l}_4{]}^{+}}\underset{\underset{s{p}^3{d}^2}{\downarrow }}{[PC{l}_6{]}^{-}}$
Solid $PB{r}_5\to \underset{\underset{s{p}^3}{\downarrow }}{[PB{r}_4{]}^{+}}[Br{]}^{-}$
Solid $N_2{O}_5\to \underset{\underset{sp}{\downarrow }}{\left[N{O}_2^{+}\right]}\underset{\underset{s{p}^2}{\downarrow }}{\left[N{O}_3^{-}\right]}$
Hence, the sum of all $s{p}^3,s{p}^2$ and $sp$ units present in solid $PC{l}_5$ , solid $PB{r}_5$ and solid $N_2{O}_5=1+1+1+1=4$