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Question

The sum of all sp3,sp2 and sp units present in solid PCl5 , solid PBr5 and solid N2O5 are:

A
4
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B
3
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C
2
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D
5
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Solution

The correct option is A 4
Solid PCl5[PCl4]+sp3[PCl6]sp3d2
Solid PBr5[PBr4]+sp3[Br]
Solid N2O5[NO+2]sp[NO3]sp2
Hence, the sum of all sp3,sp2 and sp units present in solid PCl5 , solid PBr5 and solid N2O5=1+1+1+1=4

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