The sum of all the 4 digited numbers that can be formed using the digits 1,2,5,6,7 and are divisible by 2 is
A
1166500
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B
1166400
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C
1166600
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D
1166700
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Solution
The correct option is A1166500 For number to be divisible by 2 the last digit of the number should be either 2 or 6 ∵ repetition is allowed total number formed will be =5⋅5⋅5⋅2=250 Now at units digit 2 and 6 repeated 125 times and on 10th,100th and 1000th each digit is repeated by 50 times. Hence required sum is =50(1+2+5+6+7)(10+100+1000)+125(2+6)=1166500