wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The sum of all the 4 digited numbers that can be formed using the digits 1,2,5,6,7 and are divisible by 2 is

A
1166500
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1166400
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1166600
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1166700
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1166500
For number to be divisible by 2 the last digit of the number should be either 2 or 6
repetition is allowed
total number formed will be =5552=250
Now at units digit 2 and 6 repeated 125 times and on 10th,100th and 1000th each digit is repeated by 50 times.
Hence required sum is =50(1+2+5+6+7)(10+100+1000)+125(2+6)=1166500

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon