Question

The sum of all the angles of a pentagon are

• A. ${360}^o$
• B. ${540}^o$
• C. ${720}^o$
• D. none of these

Answer 1

The correct option is B ${540}^o$

$\Rightarrow$ ABCDE is a pentagon.

$\Rightarrow$ We know that pentagon has 5 sides, so n = 5

$\Rightarrow$ Sum of interior angles of pentagon ABCDE = (n-2)$\times$180${}^{\circ }$

$\Rightarrow$ (5 - 2)$\times$180${}^{\circ }$ = 540${}^{\circ }$

$\therefore$ sum of all angles of a pentagon is 540${}^{\circ }$