The sum of all the coefficients in the expansion of ${(x + 2 y)}^{10}$ is

3^{10}

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256

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2^{10}

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512

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Solution

The correct option is A $3^{10}$
$(x + 2 y)^{10} = a_{0} x^{o} y^{10} + a_{1} x^{1} y^{9} + . . . . . . . . a_{10} x^{10} y^{\circ}$
$x = y = 1$
$(1 + 2)^{10} = a_{0} + a_{1} + a_{2} . . . . . . . . a_{10}$
$3^{10} = a_{0} + a_{1} + . . . . . . a_{10}$

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