Question

The sum of all the numbers that can be formed by taking all the digits from $2,3,4,5$ is

• A. 93,324
• B. 79,992
• C. 66,66,600
• D. 78,456

Answer 1

Answer: (A)

93,324

Total numbers ending with $2$ is $3!$
Similarly,
Total numbers ending with $3$ is $3!$
Total numbers ending with $4$ is $3!$
Total numbers ending with $5$ is $3!$
So total sum at unit digit is $(2+3+4+5)\times 6$
Similarly total sum of tens digit is $(2+3+4+5)\times 6$
Similarly total sum of hundreds digit is $(2+3+4+5)\times 6$
Similarly total sum of thousands digit is $(2+3+4+5)\times 6$
$\therefore$ Total sum is $(2+3+4+5)\times 6\times \left(1111\right)=93324$