The sum of all the real roots of the equation |x−2|2+|x−2|−2=0 is:
A
2
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B
3
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C
4
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D
None of these
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Solution
The correct option is C 4 The given equation is |x−2|2+|x−2|−2=0 Let us assume |x−2|=m thenm2+m−2=0(m−1)(m+2)=0 Only admissible value is m=1(∵m≠−2asm≥0)∴|x−2|=1⇒x−2=1⇒x=3or−(x−2)=1⇒x=1Hencex=1,3 ∴ Sum of the roots of equation = 1+ 3 = 4