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Question

The sum of all the solutions of the equation cos2x+sin22x=1 which lie in the interval[0,2π] is equal to

A
4π
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B
5π
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C
7π
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D
8π
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Solution

The correct option is C 7π
cos2x(1cos2x)=0
cos2x=0, 1
cos2x=02x=π2,3π2,5π2,7π2
cos2x=12x=0,2π,4π
Required sum =7π

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