The sum of angles of a polygon with -n- sides is- -1 Mark-A n-2-180- B n-2-90- C n-3-180- D n-1-180-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Polygon

The sum of an...

Question

The sum of angles of a polygon with $^{'} n^{'}$ sides is: [1 Mark]
A) $(n - 2) \times 180 °$
B) $(n - 2) \times 90 °$
C) $(n - 3) \times 180 °$
D) $(n - 1) \times 180 °$

Open in App

Solution

Suggest Corrections

Similar questions

Sum of interior angles of a polygon of $(n + 1)$ sides $=$

= \frac{360^{\circ}}{n}

= 180^{\circ}

n = \frac{360^{\circ}}{E x t e r i o r a n g l e}

= \frac{(n - 2) \times 180^{\circ}}{n}

In $△ N V Y$ , if $N V = V Y$ and $V Y \neq Y N$ , then which of the following is true?

(\frac{180^{0}}{n})

180^{o}

360^{o}

Join BYJU'S Learning Program