The sum of any five consecutive numbers is multiple of
5
(1, 2, 3, 4, 5; sum = 15)
(2, 4, 6, 8, 10; sum = 30),
(1, 3, 5, 7, 9; sum = 25)
Let five consecutive numbers be n-2, n-1, n, n+1, n+2
Sum = n-2+n-1+n+ n+1+n+2
= 5n
∴ Sum of any five consecutive numbers is a multiple of 5.