The sum of any three consecutive number is multiple of
3
Three
(1, 2, 3 sum = 6), (2, 4, 6 sum = 12), (1, 3, 5 sum = 9)
Let three consecutive numbers be n, n+1, n+2
Sum = n+ n+1+n+2
= 3n + 3
= 3(n+1)
∴ Sum of any three consecutive numbers is a multiple of 3.