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Question

The sum of any three distinct natural numbers arranged in ascending order is 200 such that the second number is a perfect cube. How many possible values are there for this number ?

A
4
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B
3
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C
2
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D
1
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Solution

The correct option is B 3
The second number is a perfect cube. It could be 1,8,27,64,125
but, it cannot be 1 as it is the second number
It cannot be 125 as the third number would be greater than 125 and then sum will become greater than 200
Therefore, the second number can be 8,27,64
Hence, option 'B' is correct.

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