Question

Question 54

The sum of areas of two squares with sides 4a and 4b is ___

Answer 1

$16(a^2+b^2)$
$\because$ Area of the square whose one side is $4a=(4a{)}^2=16a^2$
Area of the square with side $4b=(4b{)}^2=16b^2$
$\therefore$ Sum of areas = $16a^2+16b^2=16(a^2+b^2)$