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Question

The sum of coefficients of the two middle terms in the expansion of (1+x)2n−1 is equal to

A
(2n1)Cn
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B
(2n1)Cn+1
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C
2nCn1
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D
2nCn
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Solution

The correct option is D 2nCn
(1+x)2n1 has 2n terms.
Hence there are 2 middle terms, the nth term and the (n+1)th term.
tn=(2n1)Cn1xn1
tn+1=(2n1)Cn+11xn+11=2nCnxn
Sum of coefficients=(2n1)Cn1+(2n1)Cn=2nCn.

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