The sum of coordination number and oxidation number of the metal $M$ in the complex $[M {(e n)}_{2} (C_{2} O_{4})] C l$ (where $e n$ is ethylenediamine) is :

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Solution

The correct option is C 9
The given complex compound is [M $(e {n)}_{2} (C_{2} O_{4})$ ]Cl

Let oxidation number of M is X

$∴ X - 2 - 2 = - 1$

$X = + 3$

Now, as the coordination number is defined as the total no of binding sites attached to the metal. Hence, in the given complex coordination number is 6.
Sum of Coordination no. and oxidation state $= 3 + 6 = 9$

Hence, the correct option is C

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