The sum of coordination number and oxidetion number of the metal M in the complex $[M {(e n)}_{2} (C_{2} O_{4})]$ Cl (where en is ethylenediamine) is:

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Solution

The correct option is B 7
$[M (e n)_{2} (C_{2} O_{4})] C l$
this can be written as $[M (e n)_{2} (C_{2} O_{4})]^{+ 1}$
Consider $X$ as oxidation number,
$X - 4 - 2 = + 1$
$X = + 7$
so oxidation number is $+ 7$

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Similar questions

The sum of coordination number and oxidation number of the metal M in the complex $[M (e n)_{2} (C_{2} O_{4})] C l$ (where, en is ethylenediamine) is

M

[M (e n)_{2} (C_{2} O_{4})] C l

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[M (e n)_{2} (C_{2} O_{4})] C l

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