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Question

The sum of cubes of primes between $1$ and $6$ is equal to $40 x$ . Find the value of $x$ .

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Solution

$2^{3} + 3^{3} + 5^{3} = 40 x$

$8 + 27 + 125 = 40 x$

$160 = 40 x$

$x = \frac{160}{40}$

$x = 4$

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