Solution-: let the tens digit be x, y the ones digit. So the number will be 10x+y when we will subtract 27 from the 10x+y the number will be 10y+x So the first equation will be , 10x+y-27=10y+x we will get. 9x-9y=27 divide both sides by 9 we will get. x-y= 3 now second condtion is sum of two digits are 9 x+y= 9 We will add both equations we get , 2x=12 x= 6 , now we will plug x=6 in any equation we will get 6+y=9 y= 9-6=3 So we will plug x=6 and y= 3 in the 10x+y we will get 10(6)+3=60+3=63 answer.