The sum of eight consecutive even numbers of set A is 376. What is the sum of different set of five consecutive numbers whose lowest number is 15 more than the mean of set A?

296

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320

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324

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284

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None of these

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Solution

The correct option is B 320
Here, mean of set A $= \frac{376}{8} = 47$
Lowest number of second set = 47 + 15
= 62
$∴$ Required sum
= 62 + 63 + 64 + 65 + 66
= 320

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The sum of eight consecutive even numbers of set A is 376. What is the sum of different set of five consecutive numbers whose lowest number is 15 more than the mean of set A?

The correct option is B 320Here, mean of set A =3768=47 Lowest number of second set = 47 + 15 = 62 ∴ Required sum = 62 + 63 + 64 + 65 + 66 = 320

The correct option is B 320
Here, mean of set A $= \frac{376}{8} = 47$
Lowest number of second set = 47 + 15
= 62
$∴$ Required sum
= 62 + 63 + 64 + 65 + 66
= 320