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Question

The sum of first 10 natural numbers is____.

A
100
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B
55
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C
50
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D
90
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Solution

The correct option is B 55
The series of first 10 natural numbers is an arithmetic progressions with first tern as 1 and common difference 1. So the sum of the series will be Sn = n/2 { 2a+ ( n-1 ) d } where n is the number of terms in the series, a is the first term and d is the common difference.

S10= 10/2 { 2(1) + ( 10-1 ) 1 }

= 5 ( 2+9)

= 5 ( 11 )

= 55


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