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Question

The sum of first 10 terms of the A.P. 2,1,4,7, is:

A
115
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B
230
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C
1000
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D
620
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Solution

The correct option is D 115
First term of the A.P. is a=2
Common difference, d=a2a1
=1(2)=3

Sum of first n terms of A.P. is
Sn=n2{2a1+(n1)d}

Sum of first 10 terms of given A.P. is

S10=102{2(2)+9(3)}

=5×23

=115

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