Let a be the first term and d be the common difference.
We know that, sum of first n terms = Sn = [2a + (n − 1)d]
The given series is 1 + 3 + 5 + ......
First term = a = 1.
Common difference = d = 3 − 1 = 2
∴ S20 = [2 × 1 + (20 − 1)2]
= 10(2 + 19 × 2)
= 10(40)
= 400
Hence, the correct option is (c).