The sum of first 50 natural numbers is

1275

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1175

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none of these

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Solution

The correct option is A 1275
The sum of first n natural numbers is
$S (n) = (\frac{n}{2}) (f i r s t + l a s t)$
$S (50) = \frac{50}{2} (1 + 50)$
$S (50) = 25 \times 51$
$= 1275$

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What is the sum of the first 50 natural numbers?

n

\frac{4040!}{2^{2020} \cdot 2020!}

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