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Question

The sum of first 7 terms is 63 and sum of next of seven terms is 161 find 25th terms

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Solution

S7=63
72[2a+(71)d]=63
14a+42d=126
a+3d=9 --- (i)
Sum of next seven term is 161
S14S7=161
142[2a+13d]63=161
7(2a+13d)=224
a+132d=16 ---- (ii)
on subtracting (i) from (ii)
we get,
d=2
from (i)
a=3
a25=a+24d
=3+24×2=51

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