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Question

The sum of first 9 terms of the series.
131+13+231+3+13+23+331+3+5+...

A
142
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B
192
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C
71
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D
96
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Solution

The correct option is D 96
nth term of series =[n(n+1)2]2n2=14(n+1)2
Sum of n term =14(n+1)2=14[n2+2n+1]=14[n(n+1)(2n+1)6+2n(n+1)2+n]
Sum of 9 terms
=14[9×10×196+18×102+9]=3844=96

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