The sum of first five multiples of 3 is:

(a) 45

(b) 65

(c) 75

(d) 90

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Solution

We have to find the sum of first five multiples of 3

First five multiples of 3 are 3, 6, 9, 12 and 15

It forms an Arithmetic Progression (A.P) with

First term

We know that the sum of the n terms of an arithmetic progression

Here n = 5

Therefore

Hence option (a) is correct.

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Similar questions

In the given figure, AB || CD. If $∠ C A B = 180^{\circ}$ and $∠ E F C = 25^{\circ}$ then $∠ C E F = ?$

$(a) 65^{\circ}$

$(b) 55^{\circ}$

$(c) 45^{\circ}$

$(d) 75^{\circ}$

△ A B C

cos A cos B cos C = \frac{\sqrt{3} - 1}{8}

sin A sin B sin C = \frac{3 + \sqrt{3}}{8}

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