The sum of first $n$ consecutive odd numbers is equal to

n

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n^{2}

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n^{3}

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Solution

The correct option is B $n^{2}$
The sum of first $n$ consecutive odd numbers is equal to $n^{2}$

E.g.
$1 + 3 = 2^{2} = 4$

$1 + 3 + 5 = 3^{2} = 9$

$1 + 3 + 5 + 7 = 4^{2} = 16$

$1 + 3 + 5 + 7 + 9 = 5^{2} = 25$

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