Question

The Sum of first $n$natural numbers is given by$\frac{n(n+1)}{2}$. Find the sum of first $50$natural numbers.

Answer 1

Find the sum of first $50$natural numbers.

The Sum of first $n$natural numbers is given by$\frac{n(n+1)}{2}$

Here, $n=50$

$$\begin{gathered} thesumoffirst50naturalnumbers=\frac{n(n+1)}{2} \\ =\frac{50(50+1)}{2} \\ =\frac{50\times 51}{2} \\ =25\times 51 \\ =1275 \\ \therefore thesumoffirst50naturalnumbersis1275 \end{gathered}$$