The sum of first n odd natural numbers is n-n - 1-FalseTrue

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Sum of Terms of 1st 'n' Natural Numbers

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Question

The sum of first n odd natural numbers is n(n + 1).

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If the sum of first n even natural numbers is equal to k times the sum of the first n odd natural numbers, then k =

\frac{n (n + 1)}{2}

\frac{n (n + 1)}{2}

Prove that: 1 + 2 + 3 + ......... + n = $\frac{n (n + 1)}{2}$ i.e., the sum of the first n natural numbers is $\frac{n (n + 1)}{2}$ .

The sum S of first n even natural numbers in given by the relation S = n(n + 1). Find n, if the sum is 420.

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