The sum of first n terms of an A.P. is 5n-n2. Find the nth term of this A.P.
Given that sum of the first n terms of an AP is 5n - n2
Sn = 5n − n2
First term, a1 = S1 = 5(1) − (1)2 = 5 − 1 = 4
Sum of first two terms = S2 = 5(2) − (2)2 = 10 − 4 = 6.
Second term, a2 = S2 − S1 = 6 − 4 = 2
d = a2 − a1 = 2 − 4 = −2
an = a + (n − 1)d
= 4 + (n − 1) (−2)
= 4 − 2n + 2
= 6 − 2n.
∴ nth term of an A.P = 6 - 2n.