Question

The sum of first n terms of an AP is given by $S_n=2n^2+3n$ . Find the sixteenth term of the AP.

Answer 1

To find the 16th term , we need to subtract sum upto 15th term from sum upto 16th term

$S_{16}-S_{15}=({2.16}^2+3.16)-({2.15}^2+3.15)=65$

Hence, the 16th term is $65$