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Question

The sum of first three terms of a G.P. is to the sum of the first six terms as 125:152. Find the value of 5 times of common ratio of the G.P.

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Solution

Given S3S6=125152

a(r31)/(r1)a(r61)/(r1)=125152 [Sum of GP =a(rn1)r1 when r>1]


1r3+1=125152

or 152=125r3+125125r3=27r=35

5r=3

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