Question

The sum of five positive, consecutive integers is $115$. Find the value of the smallest integer among these.

• A. $21$
• B. $22$
• C. $23$
• D. $24$
• E. $25$

Answer 1

The correct option is A $21$

Let the five consecutive integers are $x,x+1,x+2,x+3,x+4$

$\therefore x+x+1+x+2+x+3+x+4=115$

$\Rightarrow 5x+10=115$

$\Rightarrow 5x=115-10$

$\Rightarrow 5x=105$

$\Rightarrow x=\frac{105}{5}=21$

The smallest integer $=21$