Question

The sum of four consecutive integers is $410$. What is the value of the least of these integers?

• A. 99
• B. 100
• C. 101
• D. 102

Answer 1

Answer: (C)

101

Let the four consecutive integers are $x,x+1,x+2,x+3$.

Then according to the question-

$\Rightarrow x+x+1+x+2+x+3=410$

$\Rightarrow 4x+6=410$

$\Rightarrow 4x=410-6$

$\Rightarrow 4x=404$

$\Rightarrow x=\frac{404}{4}=101$

$\therefore$ Least integer $=101$