Question

The sum of four consecutive integers is 46 then the four integers are

• A. 11,12,13,14
• B. 10,11,12,13
• C. 6,7,8,9
• D. 20,21,22,23

Answer 1

The correct option is B 10,11,12,13

$x+(x+1)+(x+2)+(x+3)=46$
$=4x+6=46$
$=4x=40$
$=x=10$
the integers are
$x_1=10,x_2=11,x_3=12,x_4=13$

$\text{correct option is B.}$