Question

the sum of four consecutive terms of A.P is 2 .The sum of 3rd and 4th terms is 11. Find the terms

Answer 1

Let first four terms be a,a+d,a+2d,a+3d
sum is a+a+d+a+2d+a+3d=2
4a+6d=2
2a+3d=1---------(1)
The sum of 3rd and 4th terms is 11
i.e., a+2d+a+3d=11
2a+5d=11----------(2)
From equation(2)$-$equation(1)
2d=10
d=5
From equation(1), 2a=1-3(5)
2a=-14
a=-7
Therefore, the terms are -7,-2,3,8......