wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The sum of four consecutive two digit odd numbers, when divided by 10, becomes a perfect square. Which of the following can possibly be one of these four members? (CAT 2006)

A
21
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
41
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
67
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
73
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 41

Option (c)

Sum of 4 consecutive odd numbers should result in a zero in the end, so as to be divisible by 10.

This happens in 7+9+1+3. Using options, we find that four consecutive odd numbers are 37, 39, 41 and 43, as the sum of these 4 numbers is 160, When divided by 10, we get 16 which is a perfect square.

Thus, 41 is one of the odd numbers.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Consecutive Numbers
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon