Question

The sum of four times a number and three times its reciprocal is 7, then that number is $\frac{3}{4}$ or 1. State true or false.

• A. True
• B. False

Answer 1

The correct option is A True

Let the number be $n$
Then, according to the given condition,

$4n+\frac{3}{n}=7$
$4n^2+3=7n$
$4n^2-7n+3=0$
$4n^2-4n-3n+3=0$
$(4n-3)(n-1)=0$
$\therefore n=\frac{3}{4},1$