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Question

The sum of HCF and LCM of two numbers is 7380.If the LCM of these numbers is 7340 more than their HCF. Find the Product of the two numbers.

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Solution

We know that,
L.C.M. + H.C.F. = product of those two no.s
let L.C.M. be x and H.C.F be y
x+y=7380-----------------------(1)
x=y+7340-----------------------(2)
By Substitution
(y+7340)+y=7380
2y=40
y=20
HCF = 20
x=y+7340
x=7360
LCM = 7360

We all know that
Product of Numbers = Product of their H.C.F and L.C.M
Product of Numbers = 20 x 7360 = 147200


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