The sum of HCF and LCM of two numbers is 7380.If the LCM of these numbers is 7340 more than their HCF. Find the Product of the two numbers.
We know that,
L.C.M. + H.C.F. = product of those two no.s
let L.C.M. be x and H.C.F be y
x+y=7380-----------------------(1)
x=y+7340-----------------------(2)
By Substitution
(y+7340)+y=7380
2y=40
y=20
HCF = 20
x=y+7340
x=7360
LCM = 7360
We all know that
Product of Numbers = Product of their H.C.F and L.C.M
Product of Numbers = 20 x 7360 = 147200