Question

The sum of infinite terms of the G.P. $1,\left(\frac{1}{3}\right),\left(\frac{1}{9}\right),$....... is

• A. 3
• B. (3/2)
• C. (2/3)
• D. 4

Answer 1

The correct option is B

(3/2)

Sum of infinite terms of G.P. whose first term is a and common ratio is r is $\frac{a}{(1-r)}$

So, the sum of infinite terms of the given G.P. is $\frac{1}{(1-(1/3\left)\right)}=\left(\frac{3}{2}\right)$